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Variable number of two-dimensional arrays into one big array


Variable number of two-dimensional arrays into one big array

By : Ibo
Date : November 19 2020, 07:01 PM
Any of those help Your head blowage will be significantly reduced if you start thinking in terms of objects and collections instead of arrays. Seriously, working with arrays like this gets way too complex really fast! This is really why OO programming was invented.
Start out with the simplest object: User. It looks like user contains first and last name, age, other stuff, and email address.
code :


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Get the number of arrays in a two dimensional array

Get the number of arrays in a two dimensional array


By : Sparsh Ghai
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further
if I run them through something like foreach($mybigarray as $value), would the $value become each sub array
How to merge two two dimensional arrays with the same number of elements per sub array in php?

How to merge two two dimensional arrays with the same number of elements per sub array in php?


By : tyroD
Date : March 29 2020, 07:55 AM
should help you out You have to assign the merged result. Pay attention to the function signature and description in the manual for array_merge():
code :
$merged_array = array_merge($data_array[0],$new_array[0]);
print_r($merged_array);
$data_array = array_merge($data_array[0],$new_array[0]);
print_r($data_array);
$data_array[0] = array_merge($data_array[0],$new_array[0]);
print_r($data_array);
bool sort ( array &$array [, int $sort_flags = SORT_REGULAR ] )
$data_array = array_merge($data_array,$new_array);
print_r($data_array);
Powershell processing arrays in a multi dimensional array after defined number

Powershell processing arrays in a multi dimensional array after defined number


By : user1886091
Date : March 29 2020, 07:55 AM
this one helps. The problem is in updating the array contents. All that's needed is a nested loop to process elements in the inner arrays with appropriate indexing. Like so,
code :
$mdarr = @((0,1,2,3,4),(5,6,7,8,9),(10,11,12,13,14))
for($i = 1; $i -lt $mdarr.Length; ++$i) {
    for($j = 0; $j -lt $mdarr[$i].Length; ++$j) {
        $mdarr[$i][$j] += 5
    }
}

$mdarr[1]
10
11
12
13
14
# This starts from 1st element (index 0), which was to be skipped. Bug
for ($i = 0; $i -lt $mdarr.Length; ++$i){

    # Loop counters $ii and $i are confusing, name is almost same
    # What's more, $i is increased instead of $ii. Bug 
    for ($ii = 0; $ii -lt $mdarr[$i].Length; ++$i){
        # This doesn't make sense. It's overwriting the whole 
        # source array-of-arrays with a single value.
        # The array cell was to be updated instead. Bug
        $mdarr = $mdarr[$i][$ii] + 5
    }
}
Creating an Array of Variable-Dimensional Arrays

Creating an Array of Variable-Dimensional Arrays


By : user2582745
Date : March 29 2020, 07:55 AM
I wish this helpful for you An array is an object. So you can create an Object array, and store 1D or 2D or 100D arrays in it:
code :
Object[] arr = new Object[3];
arr[0] = new float[][]{}; //2D
arr[1] = new float[][][][]{}; //4D
arr[2] = new float[]{}; //1D
arr[0] = new String[][]{};
arr[1] = new Object[]{};
arr[2] = new Integer[][][]{};
Create Two dimensional Array of Arrays with two variable types in Swift

Create Two dimensional Array of Arrays with two variable types in Swift


By : user3022153
Date : March 29 2020, 07:55 AM
This might help you Swift arrays are homogeneous, so you cannot store different typed elements in the same array. However, you can achieve your goals using an array of tuples instead of nested arrays.
code :
let array: [(String,Float)] = [("height",1),("width",2)]
let firstTuple = array[0]
let height = firstTuple.0
let heightValue = firstTuple.1
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