Extracting a sub-string in C#

» chash » Extracting a sub-string in C#

By : user3854415

Date : January 02 2021, 06:48 AM

this one helps. I am new to c# programming and I want to ask a question.

code :

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Extracting string constant from source code in a string using regular expressions in Python

By : ThatGuy

Date : March 29 2020, 07:55 AM

I think the issue was by ths following , How can I get a string constant from source code in a string? , Using lookbehind, to make sure the " is not preceded by a \

code :

import re

data = 'var v = "this is string constant + some numbers and \" is also included "\r\nvar v = "and another \"line\" "'
matches = re.findall( r'= "(.*(?<!\\))"', data, re.I | re.M)
print(matches)

['this is string constant + some numbers and " is also included ', 'and another "line" ']

Reqular expression - Searching a string using regex and extracting the match from the original string

By : Iresh Asanga

Date : March 29 2020, 07:55 AM

hope this fix your issue By replacing those non-digit characters, you're making your task difficult. Rather you should make a regex that extracts that part directly from the string.
The issue here is, you can't directly do \\d{12}, as the digits are not contiguous. So, let's modify that part. Since you can have 0 or more non-digit characters in between, you can use - \\d\\D* instead of \\d, and apply match that 11 times, and at the end, match single digit.

code :

"[a-zA-Z]{3}(\\d\\D*){11}\\d)"

String str = "Lorem ipsum XYZ1234-123456-12 lorem ipsum";

Pattern pattern = Pattern.compile("[a-zA-Z]{3}(\\d\\D*){11}\\d");
Matcher matcher = pattern.matcher(str);

if (matcher.find()) {
    System.out.println(matcher.group());
}

XYZ1234-123456-12

"[a-zA-Z]{3}(\\d[\\W_]*){11}\\d"

Extracting capital words and extracting the last word in a string

By : George Mills

Date : March 29 2020, 07:55 AM

seems to work fine I have a df that looks like this:

code :

df <- within(df, st_name <- sub(".*?([A-Z]{3,}).*", "\\1", x, perl=TRUE))

df <- within(df, st_type <- sub(".+? ([A-Z]+)$", "\\1", x, perl=TRUE))
#                         x           y    st_name st_type
#1     800 Block of MAIN ST  1.92908789       MAIN      ST
#2 100 Block of CHESTNUT AV  0.02487045   CHESTNUT      AV
#3   BAY ST / WELLINGTON ST -2.33411242        BAY      ST
#4     LARKIN ST / ELLIS ST -1.17946144     LARKIN      ST
#5 MAPLE ST / WELLINGTON ST  0.12913797      MAPLE      ST
#6  MEANDERING RD / MAIN ST -0.94150930 MEANDERING      ST

df$st_name <- sub(".*?([A-Z]{3,}).*", "\\1", df$x, perl=TRUE)
df$st_type <- sub(".+? ([A-Z]+)$", "\\1", df$x, perl=TRUE)

Searching for literal string with Select-String and extracting part of string

By : user2820611

Date : March 29 2020, 07:55 AM

I wish this help you Select-String, by default, uses the .NET regex engine. To do simple string matching, use the -SimpleMatch switch parameter:

code :

Select-String -Path C:\file.inf -pattern "$DeviceID" -SimpleMatch

C++: Get numbers between two string delimiters and values after extracting desired integer from string using stringstrea

By : Sultana Rajia

Date : March 29 2020, 07:55 AM

I wish did fix the issue. Fix for 2nd bug added at the end.
You should work on getting better with a debugger, I found your problem with one:

code :

while (!ss.eof()) 
    { 
    //extract the word by word from stream
    ss >> temp; 
    //Check the given word is integer or not
    if (stringstream(temp) >> found) 
         cout << "Number found: " << found << " " << endl;; 
    //no space at the end of string
    temp = ""; 
    }

while (!ss.eof()) 
    { 
    //extract the word by word from stream
    ss >> temp; 
    //Check the given word is integer or not
    if (stringstream(temp) >> found) 
         {
         cout << "Number found: " << found << " " << endl;
         foundRelevantSection = true;
         break; /* exits the while now */
         }
    //no space at the end of string
    temp = ""; 
    }

while (getline (inputFile, line) && foundRelevantSection) 
    {
    //if no matches were found, the function returns "string::npos"
    if(line.find("total") != string::npos) 
        {
        //relevant section ends now
        foundRelevantSection = false;   
        }
    else    
        {
        cout << line << endl;
        }
    }