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By : mrgrm00
Date : October 28 2020, 08:00 PM
wish helps you You could start with writing a function IndexOfSublist that can find a sublist inside a list. This has been asked many times before.
Assuming you have implemented IndexOfSublist, use it to find the first element of your result, then you could use GetRange to select the elements that you want to keep and then RemoveRange to remove the elements from the original list. code : ## Finding a sequence of alternating numbers in a list

By : SubtlePhenakism
Date : March 29 2020, 07:55 AM
help you fix your problem I'm currently trying to implement the Fourth Nelson rule from: https://en.wikipedia.org/wiki/Nelson_rules , Here's a first cut at your algorithm in straight Python:
code :
``````data = [(0, 2.5), (1, 2.1), (2, 1.7), (3, 2.0), (4, 0.3), (5, 0.8), (6, -1.2), (7, -0.5)]
n = 5

t0, x0 = data.pop(0)
outliers = []
up = bool(x0 > 0)

for t, x in data:
if (x < x0 and up) or (x > x0 and not up):
if not outliers:
outliers = [(t0,x0)]
outliers.append((t,x))
up = not up
else:
if len(outliers) >= n:
print 'outliers =', outliers
outliers = []
t0,x0 = t,x

if len(outliers) >= n:
print 'outliers =', outliers
`````` ## Finding the most consecutive sequence of any item of a list in Python

By : Khac Huynh
Date : March 29 2020, 07:55 AM
seems to work fine How can I find the most consecutive sequence of any item(integers) of a list in Python? , Use itertools.groupby() and max():
code :
``````In : my_list = [1, 3, 2, 2, 4, 5, 5, 5, 5, 6, 1, 5, 5]

In : from itertools import groupby

In : max([list(g) for _, g in groupby(my_list)], key=len)
Out: [5, 5, 5, 5]
`````` ## Finding a sequence of numbers in a multi dimensional list

By : abed alrahman
Date : March 29 2020, 07:55 AM
around this issue Using an iterator over each cell of the matrix, I've managed to get a basic idea of what you wanted to achieve in Python script.
code :
``````matrix = [[1, 1, 1, 0, 0, 0], [0, 0, 0, 0, 0, 0], [1, 0, 0, 0, 0, 0], [0, 0, 0, 1, 0, 0], [0, 0, 0, 0, 0, 0], [0, 0, 1, 0, 0, 0]]

matchCount = 0
lastNumber = None

for cell in matrix:
for number in cell:
if number == 1 and lastNumber == 1 or lastNumber == None:
matchCount += 1
if matchCount >= 3:
print("MATCH in cell " + str(cell))
lastNumber = number
matchCount = 0
lastNumber = None
`````` ## Finding a sequence in list using another list In Python

By : user1388459
Date : March 29 2020, 07:55 AM
I wish this helpful for you I have a list = [0, 0, 7] and I when I compare it against anotherList = [0, 0, 7, 0] using in it gives me False. , Here's a one-liner function that will check if list a is in list b:
code :
``````>>> def list_in(a, b):
...     return any(map(lambda x: b[x:x + len(a)] == a, range(len(b) - len(a) + 1)))
...
>>> a = [0, 0, 7]
>>> b = [1, 0, 0, 7, 3]
>>> c = [7, 0, 0, 0]
>>> list_in(a, b)
True
>>> list_in(a, c)
False
>>>
`````` ## Finding a specific sequence of elements in a list, prolog

By : Allan Sodrov
Date : March 29 2020, 07:55 AM
wish of those help Declarative wording
Almost always, when a Prolog task is formulated in a rather imperative way, the solution will be comparatively limited. This means that we typically can only use it in a few modes and directions, while other modes may even yield wrong results. Related Posts : 